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Grade: 12th pass
        
a body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and a distance of 2m in the third second. the force acting on the body is
 
one year ago

Answers : (1)

Arun
24464 Points
							

Given,m=4 kg,S1=5m,S2=2m

Distance traveled in nth second S=u+1/2a(2n-1)

S1=5=u+1/2a(2(1)-1)=u+1/2a_______1

S2=2=u+1/2a(2(3)-1)=u+5/2a———2

From 1 and 2,

We get a=-1.5m/s²,u=3.75m/s

F=ma=4*(-1.5)=-6kN

one year ago
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