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A biquadratic equation f(x) is having zeroes -2,3,5, and 7..and f(0) is 1. so the remainder of f(x) when divided by (x-1) is...please help with explanation..
A biquadratic equation f(x) is having zeroes -2,3,5, and 7..and f(0) is 1. so the remainder of f(x) when divided by (x-1) is...please help with explanation..

```
9 months ago

## Answers : (2)

Vikas TU
14149 Points
```							Der student It is not a part of JEE syllabus Please attach an image , we will happy to help you Good Luck Cheers
```
9 months ago
2074 Points
```							 dear student, biquad polynomial means it has degree 4.also, since its roots are given to be – 2, 3, 5, 7, it means that we can write f(x) as follows:f(x)= A(x – ( – 2))(x – 3)(x – 5)(x – 7)= A(x+2)(x – 3)(x – 5)(x – 7)put x=0 both sidesf(0)= A(2)(-3)(-5)(-7)or A= – 1/210so, the remainder when f(x) is divided by x – 1, would be f(1) (using remainder theorem)so, f(1)= A(1+2)(1 – 3)(1 – 5)(1 – 7)= – (1/210)(3)(-2)(-4)(-6)= 24/35option CKINDLY APPROVE :))
```
9 months ago
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