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A ball of mass 40gm impinges on a ball of mass 80 gm which is moving in the same direction as the first.If the coefficient of restitution is 3/4 and the first ball is reduced to rest after the impact find the ratio between the velocities of two ball before impact.

```
one month ago

Harsh
13 Points
```							Let the coefficient of restitution be e Newton's law of collision equation :              0−uv 2​  −0​  =−e ⟹v 2​  =eu ............(1)Applying conservation of momentum :m 1​  u 1​  +o=0+m 2​  v 2​  ∴ m 1​  u=m 2​  eu ⟹m 1​  =em 2​          ..............(2)Initial kinetic energy of the system E i​  = 21​  m 1​  u 12​  = 21​  m 1​  u 2            Final kinetic energy of the system E f​  = 21​  m 2​  v 22​  = 21​  m 2​  e 2 u 2  Also loss in kinetic energy ΔE= 21​  m 1​  u 2 − 21​  m 2​  e 2 u 2    21​  ( 21​  m 1​  u 2 )= 21​  m 1​  u 2 − 21​  m 2​  e 2 u 2   21​  ( 21​  m 1​  u 2 )= 21​  m 1​  u 2 − 21​  m 1​  eu 2                       (using (2))⟹e= 21​
```
25 days ago
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