A bag contains 3 red and 7 black balls, 2 balls are taken out at random, without replacement. If the first ball taken out is red, then what is the probability that the second taken out balll is also red?

Question

bharat bajaj · Answer

Total no. of balls = 10

The probability for taking out 1 red ball = 3/10

Probability for taking out 1 red ball out of remaining ones = 2/9 .

Hence, probability for both balls to be red = 3/10 X 2/9 = 1/15

Thanks & Regards

Bharat Bajaj

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A bag contains 3 red and 7 black balls, 2 balls are taken out at random, without replacement. If the first ball taken out is red, then what is the probability that the second taken out balll is also red?

A bag contains 3 red and 7 black balls, 2 balls are taken out at random, without replacement. If the first ball taken out is red, then what is the probability that the second taken out balll is also red?

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A bag contains 3 red and 7 black balls, 2 balls are taken out at random, without replacement. If the first ball taken out is red, then what is the probability that the second taken out balll is also red?

A bag contains 3 red and 7 black balls, 2 balls are taken out at random, without replacement. If the first ball taken out is red, then what is the probability that the second taken out balll is also red?

1 Answers

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Other Related Questions on Algebra

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