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`        a²= b+cb²=c+ac²= a+bThen 1/1+a + 1/1+b + 1/1+c=?`
2 years ago

Anish Singhal
1195 Points
```							Solution.Given : a2= b+c – (1)b2= c+a – (2)c2= a+b – (3)Now, subtract (1) – (2)a2– b2= (b+c) – (c+a)(a+b)(a-b) = – (a-b) – (4)Fom above eqn we have two resultsa+b = – 1or a-b=0But a+b = – 1 is not possible because from eqn (3), c2or a+b must be a positive integer, hence a=b holds trueNow from eqn (3), c2= 2aIn a similar way we can solve eqn (2) and (3) and we get,b=c or a2= 2bandc=a or b2= 2aAfter solving this we get, a=b=c=2.Hence the value of expression,1/(1+a) + 1/(1+b) + 1/(1+c) = 1/3 + 1/3 + 1/3 = 1. Ans
```
2 years ago
Shashank Singh
57 Points
```							a=( b+c)/a    1+a= (a+b+c)/ab= (a+c)/b    1+b= (a+b+c)/bc= (a+b)/c    1+c= (a+b+c)/c1/(1+a) + 1/(1+b) + 1/(1+c)= (a+b+c)/(a+b+c) = 1so the answer will be 1.
```
2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions