Grade 12th passAlgebra
a+b+c=0 then find the value of a2/(a2-bc)+b2/(b2-ca)+c2/(c2-ab)
2 Answers
Ashams Thomas
From a+b+c=0, a+b=-c
Substituting for -c,
a2/[a2+ b*(a+b)]+ b2/[b2 +a*(a+b)]+ (a+b)2/[(a+b)2-ab]
= a2/(a2+ab+b2) + b2/(a2+ab+b2) + a2+2ab+b2/(a2+ab+b2)
Nawal Kishore Prasad
From a+b+c=0, a+b=-c
Substituting for -c,
a2/[a2+ b*(a+b)]+ b2/[b2 +a*(a+b)]+ (a+b)2/[(a+b)2-ab]
= a2/(a2+ab+b2) + b2/(a2+ab+b2) + a2+2ab+b2/(a2+ab+b2)
=2(a^2+b^2+ab)/(a^2+b^2+c^2)
=2
Other Related Questions on algebra
How do you write “the product of 18 and q” as an algebraic expression?
How do you write “the product of 18 and q” as an algebraic expression?
algebra
Last Activity: 2 Years ago