(a-5)^2+(b-c)^2+(c~d)^2+(b+c+d-9)^2=0 then (a+b+c)(b+c+b) ?

Question

Vijay Mukati · Answer

Dear Student,

IF given equation is equal to zero and since each term is squared term, therefore each term should be equal to zero,
i.e. a-5 = 0, b – c = 0, c – d = 0 and b+c+d-9 = 0.
Using these, find the value of a, b, c, and d and then finally find the value of desired expression.

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(a-5)^2+(b-c)^2+(c~d)^2+(b+c+d-9)^2=0 then (a+b+c)(b+c+b) ?

(a-5)^2+(b-c)^2+(c~d)^2+(b+c+d-9)^2=0 then (a+b+c)(b+c+b) ?

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(a-5)^2+(b-c)^2+(c~d)^2+(b+c+d-9)^2=0 then (a+b+c)(b+c+b) ?

(a-5)^2+(b-c)^2+(c~d)^2+(b+c+d-9)^2=0 then (a+b+c)(b+c+b) ?

1 Answers

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