Samyak Jain8 Years agoa=1/X3 To find : 2 loga X 2 loga X = 2 log(1/X3) X = 2 log(X –3) X = 2 (–13) logX X …..[ logXy X = (1/Y) logX X = 1/Y] 2 loga X = –2/3