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Grade 12th passAlgebra

A^1/A=B^1/B=C^1/C
A^BC+B^AC+C^AB=729
FIND A^1/A

ASHISH TRIPATHI

10 Years agoGrade 12th pass

2 Answers

Anoopam Mishra

10 Years ago

$A^{1/A} = B^{1/B} = C^{1/C}$

$=> A^{BC} = B^{CA} = C^{AB} = K (any\ variable)$

$=> 3K = 729$

$=> K = 243$

=> $=> A^{1/A} = 243$

Sparsh Chawla

7 Years ago

A^1/A = B^1/B = C^1/C = K

A = K^A; B = K^B; C = K^C

A^BC+B^AC+C^AB=729

K^ABC+K^ABC+K^ABC=729

3K^ABC=729

K^ABC=243

K= (243)^1/ABC

A^1/A= (243)^1/ABC

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