Algebra> 9x2-6b2x-(a4-b4)=0 factorize by splitting...

9x2-6b2x-(a4-b4)=0 factorize by splitting middle term

sanjay gupta , 7 Years ago

Grade 10

2 Answers

Sami Ullah

Factorization is a bit complex instead you can use quadratic formula,but as you have asked so:

9x²-6b²x-(a^4-b^4)=0

9x²-3(2b²)x-(a^4-b^4)=0

9x²-3(b²-a²+b²+a²)x+(b^4-a^4)=0

9x²-3(b²-a²)x-3(b²+a²)x+(b²+a²)(b²-a²)=0

3x(3x-b²+a²)-(b²+a²)(3x-b²+a²)=0

(3x-b²-a²)(3x-b²+a²)=0

Hope that helps.

Please notify me for any mistakes.

Last Activity: 7 Years ago

Rishi Sharma

Dear Student,
Please find below the solution to your problem.

Factorization is a bit complex instead you can use quadratic formula,but as you have asked so:
9x²-6b²x-(a^4-b^4)=0
9x²-3(2b²)x-(a^4-b^4)=0
9x²-3(b²-a²+b²+a²)x+(b^4-a^4)=0
9x²-3(b²-a²)x-3(b²+a²)x+(b²+a²)(b²-a²)=0
3x(3x-b²+a²)-(b²+a²)(3x-b²+a²)=0
(3x-b²-a²)(3x-b²+a²)=0

Thanks and Regards

Last Activity: 5 Years ago