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64 players play a knockout tournament.Assuming that all players are of equal strength,the probability that p1 loses to p2 and p2 becomes the eventual winner is

64 players play a knockout tournament.Assuming that all players are of equal strength,the probability that p1 loses to p2 and p2 becomes the eventual winner is

Grade:12

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
3 years ago
Dear student

Let the probability of wining be p

p2 defeats p1 with prob – p

p2 over all win is-

64 players – 32 matches
32 players – 16 matches
16 players – 8 matches
8 players – 4 matches
4 players – 2 matches
2 players – 1 match

This is the method to win using knockout at each stage

Now you can figure the answer

Regards

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