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64 players play a knockout tournament.Assuming that all players are of equal strength,the probability that p1 loses to p2 and p2 becomes the eventual winner is
Dear studentLet the probability of wining be pp2 defeats p1 with prob – pp2 over all win is-64 players – 32 matches32 players – 16 matches16 players – 8 matches8 players – 4 matches4 players – 2 matches2 players – 1 matchThis is the method to win using knockout at each stageNow you can figure the answerRegards
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