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4 x +6 x =9 x . Find ‘x’.
0.Approv
Divide both sides with 6x.You will get (2/3)x +1 =(3/2)xAssume (2/3)x =y.By solving you will get a quadratic in variable y.By using quadratic formula you will be able to get the value of x.
4^x + 6^x = 9^x1 + (3/2)^x =(3/2)^2x Let (3/2)^x be 't'1 + t = t^2t^2 - t -1 =0 t=[ 1+- root (5) ] / 2 (3/2)^x = t x = lnt/ln(3/2) [substitute value of t] (3/2)
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