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Sir your answer is wrong.It is 10/21.As it was given by a book of fiitjee . So your answer is wrong. Please provide us a valid solution.
Selecting 2 children is 4C2=6Selecting 2 Non children (3M+2W)= 5C2=10Total ways of selecting 4 persons=9C4=126Probability is (6×10)/126=60/126=10/21
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