4)If 10 persons are to sit in a round table then the odds against two specific persons sitting together is a)1/9 b) 2/9 c)7 to 2 d)2 to 7

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Nishant Vora · Answer

Total number of ways = 9! favorable ways = 8! 2! Hence P =8! 2! /9! = 2/9 = 2/ 2+7 hence odd agains are 7 : 2

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4)If 10 persons are to sit in a round table then the odds against two specific persons sitting together is a)1/9 b) 2/9 c)7 to 2 d)2 to 7

4)If 10 persons are to sit in a round table then the odds against two specific persons sitting together is
a)1/9 b) 2/9 c)7 to 2 d)2 to 7

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4)If 10 persons are to sit in a round table then the odds against two specific persons sitting together is a)1/9 b) 2/9 c)7 to 2 d)2 to 7

4)If 10 persons are to sit in a round table then the odds against two specific persons sitting together isa)1/9 b) 2/9 c)7 to 2 d)2 to 7

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4)If 10 persons are to sit in a round table then the odds against two specific persons sitting together is
a)1/9 b) 2/9 c)7 to 2 d)2 to 7