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3 number selected from 1,2,3------99 find the probability that sum is divisible by 3

Ankit pathak , 7 Years ago
Grade 12th pass
anser 1 Answers
AKASH KUMAR ROY
Total numbers of sample space=99
Total number of numbers divisible by 3=34
Required probability=34C3/99C3 = 5984/156849.
Last Activity: 7 Years ago
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