Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear vardaan
(3/5)x=(x -x2-9)
L.HS = (3/5)x always positive
RHS = (x -x2-9)
coefficient of x2 is negative and discrimnent is also negative so this expresion always has negative value for all x
so no solution exists.
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