how 2 draw graph of 1/1-|x|^2

Dear jauneet

y= 1/1-|x|^2

we can write  |x|² =x²

because x² is positive for all x

for this function check the critical point

here +1 and -1 is a critical point because graph tends to infinity at these points

now

 find  Lt x→1⁺  {1/1-x² }

            =-∞

and  Lt x→1^-  {1/1-x² }

            =∞

and  Lt x→-1⁺  {1/1-x² }

            =∞

and  Lt x→-1^-  {1/1-x² }

            =-∞

and clearly at x=0 ,y=1

now draw the graph

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin