given A-M-B AM=60 BM=84 PM is perpendicular to AB PM=45 S is a circle with centre P and radius 15. Q is variable pt. on S such that AQ is maximum find BQ (the preview of the image was not available )

Dear ajinkya

AQ will be maximum if it digonally apposite to A

cos x =4/5

sinx =3/5

so PL =15cosx =12

  QL =15sinx =9

 BN =BM-NM =84-12= 72

QN=QL+LN = 45+9 =54

BQ =√(72²+54²) =90

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