Guest

cos 4 A-sin 4 A=x find cos 6 -sin 6 in terms of x

cos4A-sin4A=x


find cos6-sin6 in terms of x

Grade:10

1 Answers

Badiuddin askIITians.ismu Expert
148 Points
14 years ago

Dear ajinkya

cos4A-sin4A=x

(cos2A-sin2A)(cos2A+sin2A)=x

cos2A-sin2A =x

cos2A =x

I= cos6A-sin6A =(cos2A)3-(sin2A)3

                         =(cos2A-sin2A)[(cos2A)2+(sin2A)2 +(cos2A)(sin2A)]

                         =x[(cos2A-sin2A)2 + 3(cos2A)(sin2A)]

                           =x[x2 +3/4 (sin2A)2]

                           =x[x2 +3/4 (1-(cos2A)2)]

                            =x[x2 +3/4 (1-x2)]

                            =x [3+x2]/4

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin


Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free