Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear Mayank
x2-p(1+x)-c =0
α & β are the roots of eqn
α2-p(1+α)-c =0 or α2 =p(1+α) +c
β2-p(1+β)-c =0 or β2 =p(1+β) +c
and α + β = p
α *β =-p-c
NOw ( α2+2α+1/α2+2α+c ) + (β2+2β+1/β2+2β+c )
or 1 + (c-1)/(α2+2α+c ) + 1 + (c-1)/(β2+2β+c )
or 2 +(c-1)[1/(α2+2α+c ) +1/(β2+2β+c )]
or 2 + (c-1)[(α2+2α+c ) +(β2+2β+c ) ]/(α2+2α+c ) (β2+2β+c )
or 2 + (c-1) [α2+ β2+2(α+β)+2c]/[α2β2 +2αβ(α+β) +c(α2+β2)+4αβ+2c(α+β) +c2]
put the value
2 + -1
=1
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Badiuddin