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If at least 1 child in a family with 3 children is a boy find the prob that family have 2 of the children are boys 1) 3/7 2) 4/7 3) 3/8 4) 1/3
If at least 1 child in a family with 3 children is a boy find the prob that family have 2 of the children are boys
1) 3/7
2) 4/7
3) 3/8
4) 1/3
Dear Mayank Given at least 1 child in a family with 3 children is a boy so event 1 boy in a family ,2 boy in a family , 3 boy in a fimily are equally likily event so chances of happening any event fou of three is 1/3 so prob that family have 2 of the children are boys =1/3 Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
Dear Mayank
Given at least 1 child in a family with 3 children is a boy
so event 1 boy in a family ,2 boy in a family , 3 boy in a fimily are equally likily event
so chances of happening any event fou of three is 1/3
so prob that family have 2 of the children are boys =1/3
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
There is a probability that the family contains 1 boy,2boys or 3 boys.... so chance of each event selection is 1/3 but its not the final answer.. if one boy is there then chance of selecting that 1 boy from 3 children is 1/3 if 2 boys are there then chance of selecting one boy among them is 2/3 if 3 boys are there then chance of selecting 1 boy is 3/3 i.e., 1 Now, required probability is 1/3 * 1 / 1/3 * 1 + 1/3 * 2/3 +1/3 * 1/3 = 1/2 This is the final answer required.
There is a probability that the family contains 1 boy,2boys or 3 boys.... so chance of each event selection is 1/3 but its not the final answer..
if one boy is there then chance of selecting that 1 boy from 3 children is 1/3
if 2 boys are there then chance of selecting one boy among them is 2/3
if 3 boys are there then chance of selecting 1 boy is 3/3 i.e., 1
Now, required probability is 1/3 * 1 / 1/3 * 1 + 1/3 * 2/3 +1/3 * 1/3 = 1/2
This is the final answer required.
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