in tri.ABC, altitude AD=18 ,median BE =9√5 and median CF=15. find BC(plzz xplain)
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Hello student,Please find the answer to your question belowLetGthe centroid of△ABC,GHthe height of△GBCrelative toBCandFKthe height of△FBCrelative toBC. Recall that:CG=2/3CF=10andBG=2/3BE=6√5.Note that△BFK∼△BADand that△CGH∼△CFK, hence:FK=1/2AD=9andGH=2/3FK=6.Using Pytagoras we get:BH=12andHC=8.Therefore BC=20.
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