in triangle ABC, AB=AC B(3,6) C(7,12) G is centroid of tri.ABC .G moves on line x-y=1.find coordinates of G

ans-(8,7)(how????)xplain

Dear ajinkya

G moves on line x-y=1 

so let G is (h,h-1)

since AB =AC

so G is symittrical about B and C

so GB =GC

    GB² =GC²

 (h-3)² + (h-1-6)²  = (h-7)² +(h-1-12)²

 (h-3)² + (h-7)²  = (h-7)² +(h-13)²

(h-3)²   = (h-13)²

 open square

 h = 8

 so G =(8,7)

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin