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the integer next above (√3 +1)2m contains 2m+1 as a factor. how can we say that?
for m=0, (root3 +1)2m = 1 is an intezer
so next intezer is 2, whihc has simply 2 as one factor ( put m=0 in 2(m+1) )
for 'm' non zero
intezer next to (root3 +1)2m is (root3 +1)2m + 1 which is less than or equal to (root3 +1)2m + (root3 +1)2m i.e., 2. (root3 +1)2m
we can write 2. (root3 +1)2m as 2.(4+2(2)1/2)m which is = 2m.2. (root3 +2)m which is divisible by 2(m+1)
any other answers from other experts are welcome
regards
Ramesh
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