circle of radius r is inscribed in a quarter circular region OPQ.

the inscribed circle has chord(≠diameter)

& P-A-B-Q.

then find length of chord AB

Dear ajinkya bhole

R = r+r√2

PQ =R√2

     =2r +r√2

OD =DQ=PQ/2  =r +r/√2

PD =OD -OP

    =r +r/√2  -r√2  = r -r/√2

so AB=2AD =2√(r² -PD²)

                  put the value of PD and find AB

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