Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear ajinkya
sinΘ = R/(h-R)
and
sinΘ = r/√(r2 +h2)
so
r/√(r2 +h2) = R/(h-R)
simplyfy
R = h/[1+√(1 +(h/r)2)]
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