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Five boys and three girls are seated at random in arow.The probability that no boy sits between two girls is a.1/6 b.1/8 c.3/28 d.none

Five boys and three girls are seated at random in arow.The probability that no boy sits between two girls is


a.1/6

b.1/8


c.3/28


d.none

Grade:12

1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
9 years ago
Hello student,
Please find the answer to your question below
Considering 3 girls as one bunch plus 5 boys, it becomes = 6 persons, who can be permuted in 6! ways. 3 girls themselves, can be permuted in 3! ways.
So total ways = 6! x 3!
No. of ways 8 persons can be permuted = 8!
==> P(of the event) = (6! x 3!)/(8!) = 3/28

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