Five boys and three girls are seated at random in arow.The probability that no boy sits between two girls is

a.1/6

b.1/8

c.3/28

d.none

Hello student,
Please find the answer to your question below
Considering 3 girls as one bunch plus 5 boys, it becomes = 6 persons, who can be permuted in 6! ways. 3 girls themselves, can be permuted in 3! ways.
So total ways = 6! x 3!
No. of ways 8 persons can be permuted = 8!
==> P(of the event) = (6! x 3!)/(8!) = 3/28