Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a fxn is defined on[-1,1]and area of sq. is 4. with its vertices at (0,0) and (x,f(x)) then f(x) is... Repl


a fxn is defined on[-1,1]and
area of sq. is 4.
with its vertices at (0,0) and (x,f(x))
then f(x) is...


Grade:12

1 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
6 years ago
Ans:
Area of Square: 4
=>The sides of square are of 2 units each.
Diagonal Length:
\sqrt{(f(x))^{2}+x^{2}} = 2\sqrt{2}
(f(x))^{2}+x^{2}} = 8
f(x) = \pm \sqrt{8-x^{2}}
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free