Grade 12Algebra

a fxn is defined on[-1,1]and
area of sq. is 4.
with its vertices at (0,0) and (x,f(x))
then f(x) is...
Repl

jauneet singh

16 Years agoGrade 12

1 Answer

Jitender Singh

12 Years ago

Ans:

Area of Square: 4

=>The sides of square are of 2 units each.

Diagonal Length:

$\sqrt{(f(x))^{2}+x^{2}} = 2\sqrt{2}$

$(f(x))^{2}+x^{2}} = 8$

$f(x) = \pm \sqrt{8-x^{2}}$

Thanks & Regards

Jitender Singh

IIT Delhi

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a fxn is defined on[-1,1]andarea of sq. is 4.with its vertices at (0,0) and (x,f(x))then f(x) is... Repl

jauneet singh

1 Answer

Jitender Singh

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area of sq. is 4.
with its vertices at (0,0) and (x,f(x))
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