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a fxn is defined on[-1,1]andarea of sq. is 4.with its vertices at (0,0) and (x,f(x))then f(x) is...Repl

jauneet singh , 14 Years ago
Grade 12
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
Area of Square: 4
=>The sides of square are of 2 units each.
Diagonal Length:
\sqrt{(f(x))^{2}+x^{2}} = 2\sqrt{2}
(f(x))^{2}+x^{2}} = 8
f(x) = \pm \sqrt{8-x^{2}}
Thanks & Regards
Jitender Singh
IIT Delhi
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