Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If X= (2 raised to power  p )x  (3 raised to power  q ) x  (5 raised to power  r ) ; p,q,r are 2nd ,3rd,4th multiples of 2,3,5 respectively, then the number of Factors for X is _______

8 years ago

hi

x = 2^4* 3^9 *5^20

the number of factors are same as the nuber of divisors

(4+1)(9+1)(20+1)   including 1 and the number itself

Now you can win by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Thanks and Regards

Jitender

8 years ago

The number of factors for a number

N= a^p * b^q * c^r....

where a, b, c are prime numbers is

(p+1)(q+1)(r+1)....

Here a=2,b=3,c=5

p=4,q=9,r=20

Number of factors= 5*10*21=1050 