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If X= (2 raised to power p )x (3 raised to power q ) x (5 raised to power r ) ; p,q,r are 2nd ,3rd,4th multiples of 2,3,5 respectively, then the number of Factors for X is _______
hi
the number of factors are same as the nuber of divisors
(4+1)(9+1)(20+1) including 1 and the number itself
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Jitender
(askIITians expert)
The number of factors for a number
N= a^p * b^q * c^r....
where a, b, c are prime numbers is
(p+1)(q+1)(r+1)....
Here a=2,b=3,c=5
p=4,q=9,r=20
Number of factors= 5*10*21=1050
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