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apply the airthmatic and geometric progression concept....!
3,4,5 ... are in A.P
a=3,d=1
nth term of A.p=n+2
5,7,9 ...are in A.P
a=5,d=2
nth term of A.P=2n+3
nth term of given series=(n+2)*(2n+3)
sum of given series=sigma[(n+2)*(2n+3)]
=n/6(4n^2+9n+41)
please approved my answer.
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