Please prove it 1/a + 1/b +1/c + 1/d >= 64/(a+b+c+d)

Please prove it

1/a + 1/b +1/c + 1/d >= 64/(a+b+c+d)


1 Answers

jitender lakhanpal
62 Points
9 years ago

apply A.M>=G.M   for a,b,c,d    and for 1/a,1/b,1/c,1/d

we get     1/(abcd)^(1/4) > = 4/(a+b+c+d)

{(1/a) + (1/b) +(1/c) + (1/d)}/4 >=1/{(abcd)^4}

combining we get

the given equation

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