jitender lakhanpal
Last Activity: 11 Years ago
hi mehul
the l.c.m (a,b) = 2^4*3^3
l.c.m (b,c) = 2^3*3^2
l.c.m (c,a) = 2^4*3^3
the max value of b,c = 2^3*3^2
(2^3*3^2,2^3*3^2)
(2^3*3^2,2^3*3^1)
(2^3*3^2,2^3*3^0) similarly for 2^b
we get 7 and now interchanging b,c
we have 6 more one case when both are same
so 13 triplets