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# The odds against a husband who is 45 years old, living till he is 70 are7:5 and the odds against his wife who is now 36, living till she is 61are 5:3 . Find the probability that a) the couple will alive 25 years henceb) exactly one of them will be alive 25 years hence c) none of them willbe alive 25 years hence d) at least one of them will be alive 25 yearshence

Grade:12

## 2 Answers

jitender lakhanpal
62 Points
8 years ago

P(H)=5/12    -- the probab that husband lives 25 years hence

P(W)=3/8    -- the probab that wife lives 25 years hence

a) the couple lives 25 years hence is P(H)*P(W) = 5/32

b) exactly one of them lives 25 years hence = P(H) * P(Wbar) + P (W) * P(Hbar)

c)none of them be alive P(Hbar) *P(Wbar)

d) atleast one of them alive 1-(probab none of them alive)

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Jagmal Singh
15 Points
2 years ago

P(H)=5/12    -- the probab that husband lives 25 years hence

P(W)=3/8    -- the probab that wife lives 25 years hence

a) the couple lives 25 years hence is P(H)*P(W) = 15/96

b) exactly one of them lives 25 years hence = P(H) * P(Wbar) + P (W) * P(Hbar) = 46/96

c)none of them be alive P(Hbar) *P(Wbar) = 35/96

d) atleast one of them alive 1-(probab none of them alive) = 1-(35/96) = 61/96

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