12+22 + 32 +…..20032 = 2003*4007*334 and 1*2003 + 2*2002 + 3*2001 …..2003*1 = 2003*334*x, then x equals ? ans:: 2005Please tell me how do we do this, and explain each step precisely, thanks!

hi vaishali

the general term is   n ( 2004 - n)     n = 1 to 2003

now sigma of the nth term you will get ∑ 2004 n - ∑ n ²    

apply the formula and the given first equation you will get the answer

if you get any problem in solving get back to the forum