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12+22 + 32 +…..20032 = 2003*4007*334 and 1*2003 + 2*2002 + 3*2001 …..2003*1 = 2003*334*x
, then x equals ? ans:: 2005
Please tell me how do we do this, and explain each step precisely, thanks!
hi vaishali
the general term is n ( 2004 - n) n = 1 to 2003
now sigma of the nth term you will get ∑ 2004 n - ∑ n 2
apply the formula and the given first equation you will get the answer
if you get any problem in solving get back to the forum
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