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1 2 +2 2 + 3 2 +…..2003 2 = 2003*4007*334 and 1*2003 + 2*2002 + 3*2001 …..2003*1 = 2003*334*x , then x equals ? ans:: 2005 Please tell me how do we do this, and explain each step precisely, thanks!

12+22 + 32 +…..20032 = 2003*4007*334    and  1*2003 + 2*2002 + 3*2001 …..2003*1 = 2003*334*x


, then  x equals ? ans:: 2005


 


Please tell me how do we do this, and explain each step precisely, thanks!

Grade:12th Pass

1 Answers

jitender lakhanpal
62 Points
8 years ago

hi vaishali

 

the general term is   n ( 2004 - n)     n = 1 to 2003

 

now sigma of the nth term you will get ∑ 2004 n - ∑ n 2    

 

apply the formula and the given first equation you will get the answer

if you get any problem in solving get back to the forum

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