It has been found that A and B play a game 12 times . A wins 6 times ,B wins 4 times and they draw twice. A and B take part in a series of 3 games. The probability that they will win alternately, is

(A)5/72 (B)5/36

(C)19/27 (D)None

Question

It has been found that A and B play a game 12 times . A wins 6 times ,B wins 4 times and they draw twice. A and B take part in a series of 3 games. The probability that they will win alternately, is

(A)5/72 (B)5/36

(C)19/27 (D)None

jitender lakhanpal · Answer

hi khush

first of all find the probabilties of A winning , B winning from the first statement

and then there will be two cases

first A wins B loses then B wins A loses and then A wins and B loses

OR the other way round

apply the concept of AND OR and find the answer

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It has been found that A and B play a game 12 times . A wins 6 times ,B wins 4 times and they draw twice. A and B take part in a series of 3 games. The probability that they will win alternately, is (A)5/72 (B)5/36 (C)19/27 (D)None

It has been found that A and B play a game 12 times . A wins 6 times ,B wins 4 times and they draw twice. A and B take part in a series of 3 games. The probability that they will win alternately, is

(A)5/72 (B)5/36

(C)19/27 (D)None

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