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for 2^2+4^2+6^2+....(2n)^2 /1^2+3^2+5^2+...(2n-1)^2 to exceed 1.01,the maximum value of n is___________. ans:150.......PLS EXPLAIN THIS...

for 2^2+4^2+6^2+....(2n)^2
/1^2+3^2+5^2+...(2n-1)^2 to exceed 1.01,the maximum value of n is___________.

ans:150.......PLS EXPLAIN THIS...

Grade:12

1 Answers

jitender lakhanpal
62 Points
8 years ago

hi sriraman

 

take  2^2 common from numerator we get (1^2+2^2+3^2+....(n)^2

use the standard formula

in numerator add and subtract
                                                          2^2+4^2+6^2+....(2n)^2

 

again with some algebraic steps u will get expression for which you can use formula

and then u will get the inequality in n

 

2^2+4^2+6^2+....(2n)^2 /1^2+3^2+5^2+...(2n-1)^2  > 1.01


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