for 2^2+4^2+6^2+....(2n)^2/1^2+3^2+5^2+...(2n-1)^2to exceed 1.01,the maximum value of n is___________.ans:150.......PLS EXPLAIN THIS...

hi sriraman

take  2^2 common from numerator we get (1^2+2^2+3^2+....(n)^2

use the standard formula

in numerator add and subtract
                                                          2^2+4^2+6^2+....(2n)^2

again with some algebraic steps u will get expression for which you can use formula

and then u will get the inequality in n

2^2+4^2+6^2+....(2n)^2 /1^2+3^2+5^2+...(2n-1)^2  > 1.01

Approved