jitender lakhanpal
Last Activity: 11 Years ago
hi vivek
quite an easy question
there are 8 bulbs in 8 quadrants the coordinates are
first qudrant bulb B1 = (1,1,1)
second quadrant B2 = ( 1,-1,1 ) AND SO ON IT FORMS A CUBE OF 2 UNITS
SO ALL THE BULBS IN THE DIAGONAL WILL NOT EXPLODE
THE DISTANCE BETWEEN THE FACE DIAGONAL AND BODY DIAGONAL WILL BE GREATER THAN 2
2 ROOT 2 AND 2 ROOT 3 RESPECTIVELY SO ALL THE POSSIBLE CONFIGURATION YOU CAN EASILY FIND OUT