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find the sum of all positive real values of the parameter a, for which the equation (x^2 +4x +4a +136)^2 =16a(5x^2 +4x +136) has exactly three distinct real solutions.

shobhit gautam , 11 Years ago
Grade 11
anser 1 Answers
sudhir pal

Last Activity: 11 Years ago

(x^2 +4x +4a +136)^2 =16a(5x^2 +4x +136)

for the above given expression there is no condition under which it has exactly three real roots
because degree of the expression is four , so it would have even no. of solutions ()
if you have some other expression please rewrite again


Thanks & Regards
Sudhir,
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