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25401600
9p4/2 because of two t in permutation so answer is 1512.
No.of letters=12 with T=2 times
no of words=10!/2!
now no. of ways.. in which- P[4letters]s=7[i.eP at1 and s at 6,p at2 sat 7..up to p at 7]
||ly for =S[4 letter]P=7 ways
=>14 ways
now,
no of ways=14*10!/2!=25401600
_ _ _ _ _ _ _ _ _ _ _ _ there are 12 letters and will be seven ways of fixing p and s i.e.,7C1 such that there are 4 letters in between them and two ways of interchanging p and s i.e.,2C1 and left with 10 letters in 10 spaces and T is repeated twice so 10!/2! ......... so answer is (7c1*2c1**10!)/2!
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