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The centre of a circle passing through te points (0,0),(1,0) and touching the circle x^2+y^2=9 is?
Dear Dipankar,let m,n be the centre,then apply deistance formula for the two points mentioned..you get...m=1/2now we observe that the circle whose centre is required passes through origin.and also the centre of the other circle is at origin...hence the circles touch each-other internally,and the radius of the inner circle=1/2.radiu of outer circle=3/2.now...find n by again using distance formula...you get n=(+-)(2)^1/2Hence the Centre is [ 1/2 , (+-)root(2) ]Regards.
[ 1/2, root2 ]
The question seems to be wrong.
As the centre of the given circle is (0,0) , the required circle cannot pass through (0,0) and touch the given circle.
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