We are given 7 squares of side lengths 1, 2, 2, 2, 3, 4, 5. They can be fitted to form a rectangle, with no overlap or gaps in-between. What is the perimeter of the rectangle?
Veer Kashyap
13 Years agoGrade 11
3 Answers
Akash Kumar Dutta
Approved Tutor Answer13 Years ago
Dear Vivek, Area of all the squares=area of rectangle=1.1 +3.4 +1.9+1.16+1.25=63 sice area is also l.b... hence sides of rect.= 7 and 9.....[the sides cant be 1 and 63] perimeter=7+9=16 ANS Regards.
Akash Kumar Dutta
13 Years ago
Dear Vivek, a liitle mistake...
the perimeter=2(l+b)=2(7+9)=32units (ANS)
Regards.
Akash Kumar Dutta
13 Years ago
Dear Vivek, i am very sorry. u see my first ans. l=7 and b=9
so perimeter=32 cm.
i am very sorry if i have posted any wrong...those were mistyping.