There are p copies each of n different books. Them number of different ways in which a non-empty selection can be made frm them is

(a) (p+1)ⁿ - 1 (b) pⁿ -1 (c) (p+1) ^n-1 - 1 (d)none

Question

There are p copies each of n different books. Them number of different ways in which a non-empty selection can be made frm them is (a) (p+1) n - 1 (b) p n -1 (c) (p+1) n-1 - 1 (d)none

Jitender Singh · Answer

Ans:
Hello Student,
Please find answer to your question below

We have ‘p’ copies of each of ‘n’ different books.
Number of ways to select from p copies:
p + 1
Total no. of ways:
(p + 1)(p + 1))p + 1)................n times
(p + 1)ⁿ
Number of different ways of selection is
(p + 1)ⁿ– 1

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There are p copies each of n different books. Them number of different ways in which a non-empty selection can be made frm them is (a) (p+1) n - 1 (b) p n -1 (c) (p+1) n-1 - 1 (d)none

There are p copies each of n different books. Them number of different ways in which a non-empty selection can be made frm them is

(a) (p+1)ⁿ - 1 (b) pⁿ -1 (c) (p+1) ^n-1 - 1 (d)none

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There are p copies each of n different books. Them number of different ways in which a non-empty selection can be made frm them is (a) (p+1) n - 1 (b) p n -1 (c) (p+1) n-1 - 1 (d)none

There are p copies each of n different books. Them number of different ways in which a non-empty selection can be made frm them is (a) (p+1) n - 1 (b) pn -1 (c) (p+1) n-1 - 1 (d)none

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There are p copies each of n different books. Them number of different ways in which a non-empty selection can be made frm them is

(a) (p+1)ⁿ - 1 (b) pⁿ -1 (c) (p+1) ^n-1 - 1 (d)none