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initial budget=2000
initial no. of students= x
final no. of students= x-5
intial money given by each student= y
final money given by each student= y+20
so equation will be,
xy=2000 ..........(1)
(x-5)(y+20)=2000..................(2)
(x-5)(2000+20x)/x=2000
2000x-10000+20x^2-100x=2000x
20x^2-100x-10000=0
x^2-5x-500=0........(4)
Find x=?
then the rest procedure is very simple!!!!!!!!!!
Thankyou!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11111111
5 student attend the picnic . 200 rupees each student paid .
please post some tough questions next time.
we have let x= no of student
y=money by each
then, xy=2000
and also , (x-5)(y+20)=2000
on simplifying we get
xy+20x-5y-100=xy
putting y=2000/x
we get x^2-5x-500=0
then x=25 or -20
since -20 cannot be the no of student so x=25
20 students attended the picnic
each paid rs 100
let the no of students be ''x''
let the amount spent be ''y''
according to question,
x.y=2000 ..............(1)
since five students failed to attend =(x-5)
since the cost increased by rs.20=(y+20)
now the equation (1) becomes
(x-5)(y+20)=2000
xy+20x-5y-100=2000
20x-5y-100=0 [from (1)]
dividing throughout by 5,we get
4x-y-20=0
substitute the value of y from equation (1), i.e., y=2000/x
you will get equation like this
x.x-5x-500=0
when u solve this u wil get,x=25.
and final answer is 25 students attended the picnic
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