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y=x4/4lnx-x4/16 then dy/dx=?

y=x4/4lnx-x4/16 then dy/dx=?

Grade:11

1 Answers

Abhishekh kumar sharma
34 Points
11 years ago

i did not understand whether the above x4 is 4*x or x^4

taking x4 as x^4

we have dy/dx=[logx(4x^3)/log^2 x]-x^3/4

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