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each of the series 3+5+7+..... and 4+7+10.......... is continued to 100 terms find how many terms are identical
48 terms would be common to both the series...
first take common terms in both series..7, 13,.....so,this has a common difference of 4 starting with 7.
now last term of the given series are 201 and 301 respectively..So we can end our calculation by checking upto 201.
201=7+(n-1)4----->n=48(we have to take integer nearest to it)
the answer is 33 ..............if the answer is correct then inform me i will explain if u need it and if it correct
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