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Solve:
loge(1+x)1+x(1-x)1-x
Prove that:
logea - logeb = (a - b)/a + 1/2 (a - b)2/a2 + 1/3 (a - b)3/b3
first question is not so clear
second question can be proved by using expansions of logarithms ... which can be found in any differential calculus books
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