0

Guest

Courses New

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is______.

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is______.

Grade:11

8 Answers

Aman Bansal
592 Points
11 years ago

Dear Shiva,

P(same house) = 1/3 * 1/3 = 1/9

Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. 

http://www.askiitians.com/packages/packages.aspx

So start the brain storming…. become a leader with Elite Expert League ASKIITIANS

Thanks

Aman Bansal

Askiitian Expert

upender surepally
126 Points
11 years ago

1/9

Shaurya Gupta
41 Points
11 years ago

Let 1 person select 1 house. Then the probability that 2nd and 3rd also apply for the same house is 1/3 X 1/3 as total houses are 3.

= 1/9

G Ashwin -
24 Points
11 years ago

Each person has 1/3 chance on each house.

there are 3 houses.

so,

p=1/9

Humanshu Parkhade
36 Points
7 years ago
For particular house probability is 1/3., probability that all 3 apply for same house is 1 by (1/3 ร—1/3 ร—1/3 )ร—3
Sawan Yadav
34 Points
6 years ago
Total no. Of ways a person can select a house=3C1=3Now, probability of all(selecting same house)=(1/3*1/3*1/3)*3=1/9 (ans)
Aman Gupta
13 Points
5 years ago
Let the three persons be a, b, c and the three houses be p, q, r. The event of selecting a house is an independent event. So, the probability of a, b, c selecting the house p is 1/3x1/3x1/3. Similarly, the probability of a, b, c selecting the house q is 1/3x1/3x1/3. Therefore the total probability will be 3x(1/3x1/3x1/3)=1/9
Rishi Sharma
askIITians Faculty 646 Points
3 years ago
Dear Student,
Please find below the solution to your problem.

Let 1 person select 1 house. Then the probability that 2nd and 3rd also apply for the same house is 1/3 X 1/3 as total houses are 3.
= 1/9

Thanks and Regards

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions ยป

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More