Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

find the sum of the series:-1+(1+3)+(1+3+5).............n terms

find the sum of the series:-1+(1+3)+(1+3+5).............n terms

Grade:

2 Answers

Har Simrat Singh
42 Points
8 years ago

In this series the nth term is given by 

(1+3+5+.................r) Terms which is an AP of first term 1 and cd 2 therefor sum upto r is r/2[2+(r-1)2] = r^2

Hence of series is Sigma(r^2) = n(n+1)(2n+1)/6

G Ashwin -
24 Points
8 years ago

after simplification, we see that it is just the same as n^2.

Sum=n(n+1)(2n+6)/6

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free