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Grade 12Algebra

Submit your detailed Question here...if ax^2 + bx +6 = 0 does not have 2 distinct real roots, , then least value of 3a + b is?

Profile image of Sajin SS
13 Years agoGrade 12
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3 Answers

Profile image of vinay kant
13 Years ago

Dear Sijin,

According to given condition,

D<0;

b^2 - 24a <0

b^2 < 24a

as it does not have real roots thus

its discriminant is equal to zero

i.e.         b^2 - 4*a*6= b^2 - 24a=0

          a = b^2 / 24

     now take  y=3a+b

put value of a and differentiate it and you will get

dy/da=b/4 +1=0

b= -4

is the minimum value.............


    

Profile image of Sajin SS
13 Years ago

Yes..after that?

Profile image of mycroft holmes
13 Years ago