Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If 4x^2 + 9y^2 + 16z^2 -6xy - 12yz - 8zx = 0 then x,y,z are in AP , GP or HP???

  If 4x^2 + 9y^2 + 16z^2 -6xy - 12yz - 8zx = 0 then x,y,z are in AP , GP or HP???

Grade:12

2 Answers

Gyanesh Gupta
5 Points
8 years ago

multiply by 2 both sides then get an exp of this fom

(2x-3y)^2 +(3y-4z)^2+(4z-2x)^2=0

so, 2x=3y=4z=a (say)

x=a/2, y=a/3, z=a/4

so x,y,z in H.P.

G Ashwin -
24 Points
8 years ago

this can be done by hit and trial.

put values in x,y,z as of ap,gp,hp.

the one which satisfies the equation is the solution

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free